# Find a vector perpendicular to the line

**a vector perpendicular**to a 2d

**vector**is a very simple formula: Code (csharp): public static Vector2 Orth ( Vector2 v) {. return new Vector2 (- v.y, v.x); } You can just do that with a Vector3.

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**line**passing through the point (1,0,8) and

**perpendicular**to the plane x + 3 y + z = 3 Let r 0 = i + 0 j + 8 k A

**line**

**perpendicular**to the plane x + 3 y + z = 3 has the same direction as a normal

**vector**to the plane, which is n = < 1 , 3 , 1 >.

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**tell**us information about the

**line**, so we need to know how to

**find**all three types of equations. The

**vector**equation of a

**line**is given by. r = r 0 + t v r=r_0+tv r = r 0 + t v. where r 0 r_0 r 0 is a point on the

**line**and v v v is a parallel

**vector**.The parametric equations of a

**line**are given by. So, letβs choose the first, one, three, one. And letβs call the other point π΅. We can

**find**the direction

**vector**of the

**line**π by taking the difference of the position

**vectors**of the points π΅ and π΄, π to π΅ and π to π΄, respectively.. Apr 25, 2017 · To construct a

**vector**that is

**perpendicular**to another given

**vector**, you can use techniques based on the dot-product and.

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**= normalize(p1 - p0).**To calculate a perpendicular vector we can use the cross product with (0, 0, 1). Which results in:

**d_left**= (-d.y, d.x) d_right = (d.y, -d.x) You haven't said how your coordinate system is aligned, so d_left might become d_right and vice versa. You then get the desired points with:.